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            GRE考試技巧數學重要考點AP介紹

            時間:2024-07-15 16:21:28 GRE 我要投稿
            • 相關推薦

            GRE考試技巧關于數學重要考點AP介紹

              新GRE考試技巧:數學重要考點AP

            GRE考試技巧關于數學重要考點AP介紹

              新gre考試實施以來,不僅對寫作部分茫然不知所措,就連我們所擅長的數學也甚是擔憂,相信這其中的原因還是由于考生在新gre數學復習時沒有把基礎打牢。如果新版gre數學基本考點都沒有復習到,如何能拿到分數呢?所以說,想要新版gre數學考好,復習的時候一定要把基本概念和重要考點都弄扎實。 天針對新版gre數學復習,小編給大家整理的是關于平均數的相關內容,這些概念在考試中一定會考到的。希望考生能再接再厲,取得一個好成績,突破新版gre數學難的困境。

              AP

              Average of n numbers of arithmetic progression (AP) is the average of the smallest and the largest number of them. The average of m number can also be written as x + d(m-1)/2.

              Example:

              The average of all integers from 1 to 5 is (1+5)/2=3

              The average of all odd numbers from 3 to 3135 is (3+3135)/2=1569

              The average of all multiples of 7 from 14 to 126 is (14+126)/2=70

              remember:

              Make sure no number is missing in the middle.

              With more numbers, average of an ascending AP increases.

              With more numbers, average of a descending AP decreases.

              AP:numbers from sum

              given the sum s of m numbers of an AP with constant increment d, the numbers in the set can be calculated as follows:

              the first number x = s/m - d(m-1)/2,and the n-th number is s/m + d(2n-m-1)/2.

              Example:

              if the sum of 7 consecutive even numbers is 70, then the first number x = 70/7 - 2(7-1)/2 = 10 - 6 = 4.

              the last number (n=m=7)is 70/7+2(2*7-7-1)/2=10+6=16.the set is the even numbers from 4 to 16.

              Remember:

              given the first number x, it is easy to calculate other numbers using the formula for n-th number: x+(n-1)

              AP:numbers from average

              all m numbers of an AP can be calculated from the average. the first number x = c-d(m-1)/2, and the n-th number is c+d(2n-m-1)/2, where c is the average of m numbers.

              Example:

              if the average of 15 consecutive integers is 20, then the first number x=20-1*(15-1)/2=20-7=13 and the last number (n=m=15) is 20+1*(2*15-15-1)/2=20+7=27.

              if the average of 33 consecutive odd numbers is 67, then the first number x=67-2*(33-1)/2=67-32=35 and the last number (n=m=33) is 67+2*(2*33-33-1)/2=67+32=99.

              Remember:

              sum of the m numbers is c*m,where c is the average.

              由于美國數學基礎教育的難度增加導致數學考試越來越難,但新gre數學復習考點都是高中時候學到的知識點,考生不要過于緊張,把基本概念弄明白,再記住一些新版gre數學必備的詞匯,那么相信新版gre數學應該沒有問題。

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